S82856 |
BIBS 39 |
源葉(MedMol) | 99% |
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- 產(chǎn)品描述: BIBS 39 is a new nonpeptide angiotensin II (AII) receptor antagonist. Target: Angiotensin Receptor in vitro: BIBS 39 displaces [125I] AII from its specific binding sites with a Ki value of 29 ± 7 nM for the AII subtype 1 (AT1) receptor and a Ki value of 480 ± 110 nM for the AII subtype 2 (AT2) receptor. BIBS 222 shows a Ki value of 20 ± 7 nM for the AT1 subtype and a Ki value of 730 ± 170 nM for the AT2 subtype. BIBS 39 is 17 times more selective for the AT1 subtype and BIBS 222 37 times. BIBS 39 shifts the AII concentration-contractile response curves in isolated rabbit aorta to the right in a parallel fashion. in vivo: In pithed rats, BIBS 39 dependently shifts the dose-response curve of AII to the right without affecting the maximal response. BIBS 222 also causes parallel shifts to the right but a significant reduction of the maximal responses was observed at 3 and 10 mg/kg i.v. These results show that the benzimidazole derivatives BIBS 39 is a potent and selective AII receptor antagonists. Substitution with a benzimidazole moiety results into a considerable loss of selectivity for the AT1 receptor subtype compared with an imidazole moiety as, for instance, in DuP 753.BIBS 39 is a new nonpeptide angiotensin receptor blockers that has affinity for both AT1- and AT2-receptors, is also a potent antagonist of the cardiovascular effects of AII in pithed rabbits.
- 靶點(diǎn): Angiotensin Receptor;RAAS
- 參考文獻(xiàn):
1. Zhang J, et al. Characterization of BIBS 39 and BIBS 222: two new nonpeptide angiotensin II receptor antagonists. Eur J Pharmacol. 1992 Jul 21;218(1):35-41. 2. Zhang J, et al. Hemodynamic effects of angiotensin II and the influence of angiotensin receptor antagonists in pithed rabbits. J Cardiovasc Pharmacol. 1995 May;25(5):724-31.
- 溶解性: Soluble in DMSO
- 保存條件: 2-8℃
- 配置溶液濃度參考:
1mg 5mg 10mg 1 mM 1.906 ml 9.53 ml 19.06 ml 5 mM 0.381 ml 1.906 ml 3.812 ml 10 mM 0.191 ml 0.953 ml 1.906 ml 50 mM 0.038 ml 0.191 ml 0.381 ml
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輸入產(chǎn)品批號(hào):
本計(jì)算器可幫助您計(jì)算出特定溶液中溶質(zhì)的質(zhì)量、溶液濃度和體積之間的關(guān)系,公式為:
質(zhì)量 (mg) = 濃度 (mM) x 體積 (mL) x 分子摩爾量 (g/mol)